Question

Sabendo que log 2 = a   e    log 3 = b, calcule em função de a e b:
a) log 5 

Answer 1

log 5 = log (60/12) = log (3x2x10)/log (3x2x2) = (log 3+log2+log10) / (log 3 + log 2+ log 2) = (b+a+1) / (b+a+a) = (a+b+1) / 2a+b