Question

Sabendo que log 2 ≈ 0,301, log3 ≈ 0,477 e considerando loga = log10a, uma boa aproximação para log0,0036 é:

Answer 1

$Resolu\c{c}\~ao \to \left[\begin{array}{ccc}log\ 0,0036 = y\\\\log\ \frac{36}{10000} = y\\\\log\ 36 - log\ 10000=y\\\\log\ 2^2*3^2-log\ 10^4=y\\\\log\ 2^2+log\ 3^2-4*log\ 10=y\\\\2*log\ 2+2*log\ 3-4=y\\\\2*0,301 + 2*0,477-4=y\\\\0,602+0,954-4 = y\\\\\boxed{\boxed{y \approx-2,444}}\end{array}\right$

Espero ter ajudado. =^.^=