Question

sabendo que A×B=C+D, determine o monômio D, sendo A=
$2 {x}^{2} {y}^{3}$
B=
$- 4xy$
e C=
$- 14 {x}^{3} {y}^{4}$
​

Answer 1

Resposta:

$a \times b = c + d \\ 2 {x}^{2} {y}^{3} \times ( - 4xy) = - 14 {x}^{3} {y}^{4} + d \\ - 8 {x}^{3} {y}^{4} + 14 {x}^{3} {y}^{4} - d = 0 \\ 6 {x}^{3} {y}^{4} - d = 0 \\ - d = - 6 {x}^{3} {y}^{4} \times ( - 1) \\ d = 6 {x}^{3} {y}^{4}$