Question

Sabendo que 2x= log 72 + log 2/3 - log 48, qual é o valor de x?

 

 

 

 

 

 

 

 

Me ajudem!

Answer 1

$log_{b}(a)+log_{b}(c) <=> log_{b}(a*c)$
$log_{b}(a)-log_{b}(c) <=> log_{b}(a/c)$
$log(1)=0$
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$2x = log(72)+log(2/3)-log(48)$
$2x=log(72*[2/3]/48)$
$2x=log(24*2/48)$
$2x=log(1*2/2)$
$2x=log(1)$
$2x=0$
$x=0$