Question

Sabendo log2= 0,3010 e log3= 0,4771 calcule os seguintes logaritmos:

A=Log 10
B= Log 36
C= Log 1,2

Answer 1

A=Log 10 = 1 
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B= Log 36 = log(2² . 3²) ==> 2log2 + 2 log3 ==> 2(0,3010) + 2(0,4771)

 0,6020 + 0,9542 ==> 1,5562
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C= Log 1,2 ==> log12/10 ==> log 12 - log10 ==> log(2².3) - 1

2log2 + log3 - 1 ==> 2(0,3010) + 0,4771 - 1

0,6020 + 0,4771 - 1 ==> 0,0791