Question

resultado da equacao x2+12x+36=0

Answer 1

Resolvendo a equação, temos:

$x^{2}+12x+36=0$

$\Delta=b^{2}-4\cdot a\cdot c$
$\Delta=12^{2}-4\cdot1\cdot36$
$\Delta=144-144$
$\Delta=0$

$x=\dfrac{-b\pm\sqrt{\Delta}}{2a}$

$x=\dfrac{-12\pm\sqrt{0}}{2\cdot1}$

$x=\dfrac{-12}{2}=-6$

$\Longrightarrow\;x_{1}=x_{2}=-6$

$S=\{-6\}$

Answer 2

x²+12x+36=0
a=1
b=12
c=36
Delta=12²-4*1*36
Delta=144-144
Delta=0

x'=-12+V0/2*1
x'=-12+0/2
x'=-12/2
x'=-6

x''=-12-0/2
x''=-12/2
x''=-6

Solução= {-6}