Question

responde prfv essas duas questões e mim ensinar expressões numéricas 6°​

Answer 1

Resposta:

Explicação passo-a-passo:

e)

$(13-1)^{2}:[\sqrt{64}:2^{3}+(81:3^{2}-8).3]+6^{2}$ =

$(12)^{2}:[8:8+(81:9-8).3]+36$ =

$144:[1+(9-8).3]+36$ =

$144:[1+1.3]+36$ =

$144:4+36$ =

$36+36$ =

$72$

f)

$[(2+2^{3})^{3}-(64-2^{2}).2^{4}]^{2}+(8-18:3^{2})^{2}$ =

$[(2+8)^{3}-(64-4).16]^{2}+(8-18:9)^{2}$ =

$[(10)^{3}-(60).16]^{2}+(8-2)^{2}$ =

$[1000-960]^{2}+(6)^{2}$ =

$[40]^{2}+(6)^{2}$ =

$[1600+36$ =

$[1636$