Question

Responde aq ligeiro!
Determine o valor de cada potência :

3⁻³ =


(-2)⁻⁵ =


6⁻² =


0,3⁻¹ =


(3⁻²)⁻¹ =


3⁻⁵ =


2⁻⁴ =


(-2)⁻⁹ =


Determine o valor de cada potência com base fracionária e expoente inteiro

a) (1/2)-¹=

b) (3/4) -¹=

c) (2/5)⁻⁵=

d) (1/8)⁻³=

e) (-6/5)⁻¹=

f) (-4/9)⁻²=

g) (-3/7)⁻³=

h) (-9/11)⁰=

Answer 1

Explicação passo-a-passo:

3-³= 1/3³= 1/27

(-2)-⁵= (- 1/2)⁵= - 1/32

6-²= (1/6)²= 1/36

0,3-¹= (3/10)-¹= (10/3)¹= 10/3

(3-²)-¹ = 3²= 9

3-⁵= (1/3)⁵= 1/243

2-⁴= (1/2)⁴= 1/16

(-2)-⁹= ( - 1/2)⁹= - 1/512

a) (1/2)-¹= (2/1)¹= 2¹= 2

b) (3/4)-¹= (4/3)¹= 4/3

c) (2/5)-⁵= (5/2)⁵= 3125/32

d) (1/8)-³= (8/1)³= 8³= 512

e) (-6/5)-¹= (- 5/6)¹= -5/6

f) (-4/9)-²= (- 9/4)²= + 81/16

g) (-3/7)-³= (- 7/3)³= - 343/27

h) 1