Question

responda usado formula de bhaskara
x^{2} -4x=-6+3x

Answer 1

Organizando a equação:
${x}^{2} - 4x = - 6 + 3x \\ {x }^{2} - 4x - 3x + 6 = 0 \\ {x}^{2} - 7x + 6 = 0 \\ delta \: = {b}^{2} - 4ac \\ delta \: = {( - 7)}^{2} - (4 \times 1 \times 6) \\ delta = 25 \\ x1 = \: \frac{ - b \: + \sqrt{delta} }{2a} \\ x1 = \frac{ - ( - 7) + \sqrt{25} }{2} \\ x1 = 6 \\ x2 = \frac{ - ( - 7) - 5}{2} \\ x2 = 1$
x1 = 6
x2 = 1