Question

Resolver utilizando a fórmula de Báskara: Δ= b²-4.a.c x = – b ± √Δ
2a
a) x² – 3x – 4 = 0 b) x² – x – 12 = 0 c) 2x² + 5x – 3 = 0

Answer 1

Explicação passo-a-passo:

a)x^2-3x-4=0

/\=b^2-4.a.c

/\=(-3)^2-4.1.(-4)

/\=9+16

/\=25

x=-b+- raiz de delta/2.a

x=-(-3)+5/2

x'=+3+5/2

x'=4

x"=+3-5/2

x"=-2/2

x"=-1

b)x^2-x-12=0

(x+3).(x-4)=0

x+3=0

x-4=0

x'=-3

x"=+4

c)2x^2+5x-3=0

(x+3).(2x-1)=0

x+3=0

2x-1=0

x'=-3

x"=+1/2