Question

resolver usando bhaskara
x ao quadrado menos 6x mais 9 igual a 0

Answer 1

x² - 6x + 9 = 0
Delta = b² - 4ac
Delta = 36 - 4(1)(9)
Delta = 36 - 36
Delta = 0

X = (-b +- raiz delta) / 2a
X = (6 +- 0) / 2
x' e x" = 6/2 = 3

Answer 2

x²-6x+9=0
Δ = b²-4a.c.
Δ = - 6² - 4.1.9
Δ = 36 - 4.9
Δ = 36-36
Δ = 0
x = -b +/- √Δ
     ----------------
           2a
x = -(-6) +/- √0
      ----------------
             2
x = 6 +/- 0
     -----------
          2
x¹ e x² =  6
             ----
               2
x¹ e x²   =  3