Question

Resolver o sistema.
4x² + 2xy + y2 - 37
2% - y = 1​

Answer 1

Resposta:

{4x^2+2xy+y2-37

{2%-y= 1

2%-y = 1

2 - y = 1

100

1 -y = 1

50

-y= 1 - 1

50

-y= 50-1

50

-y= 49 ×(-1)

50

y= - 49

50

4x^2+2xy+y2-37

4x^2+2x . -49 + -49 . 2-37

50 50

2 (2x^2+x . -49 + -49 . 37)

( 50 50 )

2 (2x^2.-49 + 1813)

( 50 50 )

2. 1 (100x^2.-49 + 1813)

50

1 (100x^2.-49 + 1813)

25

ou

0,04(100x^2.-49 + 1813)

Espero ter ajudado!!

:)