Question

Resolver em R a inequação f) (2x² + 4x + 5 / 3x² + 7x + 2) <-2

Answer 1

(2x² + 4x + 5 / 3x² +7x + 2 ) < -2

2x² + 4x + 5 > - 2 ( 3x² +7x +2)
2x² +4x + 5 > - 6x² - 14x - 4
2x² + 6x² + 4x+14x + 5 + 4 > 0
8x² +18x + 9 > 0

Δ= 324- 288
Δ=36
resolvendo
x= -18 + ou √36 / 2.8
x= -18 + ou - 6 / 16
x'= -18 + 6 / 16 = -12/16=-3/4
x"= -18 -6/16=-24/16=-3/2