Question

resolver em ir as equaçoes:
2x2-7x+3=0

Answer 1

2x2-7x+3 = 0

delta = (-7)^2 -4.2.3 = 49 - 24 = 25

x = 7 +/-V25 ==> x = 7+/-5
           2.2                   4
 
 x1 = 7 + 5 ==> x1 = 3
            4 

x2 = 7 - 5 ==> x2 = 2 ou  x2  = 1
            4                4                 2

Answer 2

$2 x^{2} -7x+3=0= \Delta= b^{2} -4.a.c= \Delta= -7^{2} -4.2.3=49-24=25 x^{1} =-+(-7) \sqrt{25}/ 2.2=7-5/4=2/4=1/2  x^{2} =-+(-7) \sqrt{25} /2.2=7+5/4=12/4=3$


S{1/2,3}