Question

resolver as equações
2^2x - 2^x+3 + 16=0

2^x-4=1/4

Answer 1

2^2x-2^(x+3)+16=0
(2^x)^2-2^x.2^3+16=0
2^x=y
y^2-8y+16=0
(y-4)^2=0
y-4=0
y=4
2^x=4
x=2