Question

Resolver a equação de segundo grau

Answer 1

$3x^2 - 2x - \dfrac{1}{2} = 0 \\ \\ \dfrac{6x^2 - 4x - 1}{2} =0 \\ \\ \\ 6x^2 - 4x - 1 = 0$


$x = \dfrac{-b \pm \sqrt{b^2 -4*a*c}}{2*a}$

a=6, b=−4, c=−1

Δ=b^2−4ac
Δ=(−4)2−4*(6)*(−1)
Δ=16+24
Δ=40

$x = \dfrac{-(-4) \pm \sqrt{40}}{2*6} \\ \\ \\ x = \dfrac{4\pm 2\sqrt{10}}{12} \\ \\ \\ x' = \dfrac{4 + 2\sqrt{10}}{12} \\ \\ \\ x' = \dfrac{2 + \sqrt{10}}{6} \\ \\ \\ x'' = \dfrac{4 - 2\sqrt{10}}{12} \\ \\ \\ x'' = \dfrac{2 - \sqrt{10}}{6}$

S  = {$\dfrac{2 + \sqrt{10}}{6}, \ \dfrac{2 - \sqrt{10}}{6}$}