Question

Resolver:
1) seja y = kx calcule k sabendo que:



a) x = 3 = > y = 6


b) x = 6 => y = 3


c) x = 1 => y = 1


d) x = 5 => y = 7


e) x = 3/7 (fração) => y = 4/5



2) seja y = k/x calcule k sabendo que:


a) x = 2 => y = 2


b) x = 3 => y = 6


c) x = 10 => y = 2


d) x = 1/6 => y = 6


e) x = 3/4 => y = 2


f) x = 9/5 => y = 5/9


g) x = 2/7 => y = 7/6


h) x = 3 => y = √3



pv me ajudem!!

Answer 1

y = kx

a) 6 = 3k

k = 2

b) 3 = 6k

k = 1/2

c) 1 = 1k

k = 1

d) 7 = 5k

k = 7/5

e) 4/5 = 3k/7

k = 4/5 . 7/3

k = 28/15

2) y = k/x

a) 2 = k/2

k = 4

b) 6 = k/3

k = 18

c) 2 = k/10

k = 20

d) 6 = k / 1/6

k = 6 . 1/6

k = 1

e) 2 = k / 3/4

k = 2 . 3/4

k = 3/2

f) 5/9 = k / 9/5

k = 5/9 . 9/5

k = 1

g) 7/6 = k / 2/7

k = 7/6 . 2/7

k = 14/42 ou 1/3

h) √3 = k / 3

k = 3√3