Question

Resolva : x2-10x+25=0 (Delta e Bhaskara)

Answer 1

x² - 10x + 25 = 0

a = 1
b = -10
c = 25

Delta:
Δ = b² - 4ac
Δ = (-10)² - 4 * 1 * 25
Δ = 100 - 100
Δ = 0
      Bhaskara:
      x = - b ± √Δ / 2a
      x = - (-10) ± √0 / 2 * 1
      x = 10 ± 0 / 2
      x' = 10 - 0 / 2 = 10 / 2 = 5
      x'' = 10 + 0 / 2 = 10 / 2 = 5

Espero ter ajudado. Valeu!