Question

Resolva por 15 pontos!!!!
(x+3)^2=1
Explique!

Answer 1

$Resolu\c{c}\~ao\to \left\{\begin{array}{ccc}(x+3)^2=1\\\\(x+3) = \pm\sqrt{1}\\\\x+3 = \pm 1\\\\ x+3=-1\\\\\boxed{\boxed{x = -4}}\\\\x+3=1\\\\ \boxed{\boxed{x = -2 }}\end{array}\right$

Espero ter ajudado. :))

Answer 2

.
$(x+3)^2=1 \\ (x+3)=\pm \sqrt{1} \\ x+3=\pm1 \\ \\ x+3=1 \\ x=1-3 \\ x=-2 \\ \\ x+3=-1 \\ x=-1-3 \\ x=-4$


pode fazer assim também

$(x+3)^2=1 \\ x^{2} +6x+9=1 \\ x^{2} +6x+9-1=0 \\ x^{2} +6x+8=0$

Δ=b²-4ac
Δ=6²-4(8)
Δ=36-32
Δ=4
√Δ=√4 =±2

$x= \frac{-b\pm \sqrt{delta} }{2a} = \frac{-6\pm2}{2} \\ \\ x'= \frac{-6+2}{2}=- \frac{4}{2} =-2 \\ \\ x"= \frac{-6-2}{2} =- \frac{8}{2} =-4$