Question

Resolva pelo teorema de Pitágoras

Answer 1

Resposta:

4)

$e {}^{2} =12 {}^{2} + 5 {}^{2} \\ e {}^{2} = 144 + 25 \\ e = \sqrt{169} \\ e = 13u.c.$

x^2=8^2+6^2

x^2=64+36

x^2=100

$x = \sqrt{100} \\ x = 10u.c.$

Explicação passo-a-passo:

BONS ESTUDOS!

Answer 2

Torema de Pitágoras

• Cálculo:

$\boxed{ \begin{array}{lr} \\ \large \sf {h}^{2} = {c}^{2} + {c}^{2} \\ \\ \large \sf \: {e}^{2} = {12}^{2} + {5}^{2} \\ \\ \large \sf \: {e}^{2} = 144 + 25 \\ \\ \large \sf \: e = \sqrt{169} \\ \\ \boxed{ \red{\large \sf \: e = 13}} \\ \: \end{array}}$

➖➖➖➖➖➖➖➖➖➖➖➖➖➖➖➖➖

$\boxed{ \begin{array}{lr} \\ \large \sf {h}^{2} = {c}^{2} + {c}^{2} \\ \\ \large \sf \: {x}^{2} = {8}^{2} + {6}^{2} \\ \\ \large \sf \: {x}^{2} =64 + 36\\ \\ \large \sf \: x = \sqrt{100} \\ \\ \boxed{ \red{\large \sf \: x = 10}} \\ \: \end{array}}$