Question

Resolva os seguintes sistemas aplicando a regra de cramer: A) {3x -y = 1
2x +3y =8 B) {x -y =3
2x +2y =6

Answer 1

A)3x-y=1
2x+3y=8
3x-y=1
3x=1+y
x=$\frac{1+y}{3}$
2x+3y=8
2$\frac{1+y}{3}$+3y=8
2$\frac{1+y}{3}$+$\frac{3y}{1}$=8
$\frac{2+2y+9y}{3}$=8
$\frac{2+11y}{3}$=8
$\frac{11y}{3}$=8$\frac{-2}{3}$
$\frac{11y}{3}$=$\frac{24-2}{3}$
$\frac{11y}{3}$=$\frac{22}{3}$
11y=22
3x-y=1$\left \{ {{y=2} \atop {x=1}} \right.$

B)x-y=3
2x+2y=6
x-y=3
x=3+y
2x+2y=6
2(3+y)+2y=6
6+2y+2y=6
2x+2y=3$\left \{ {{y=0} \atop {x=3}} \right.$
espero ter ajudado :)