Matemática, perguntado por rozanianeves89, 3 meses atrás

resolva o sistema x+y+z=5
1x -1y +2z=3
3x-1y+5z =7

Soluções para a tarefa

Respondido por grecosuzioyhdhu
1

Explicação passo a passo:

x + y + z = 5>>>>>>>>>>>>>>>>>>>1

1x -1y +2z=3>>>>>>>>>>>>>>>>>>>>2

3x-1y+5z =7>>>>>>>>>>>>>>>>>>>3

CALCULANDO >>>>>>>>>>>>>>>>>1 e >>>>>>>>>>2

1x + 1y + 1 z = 5>>>>>>>>>>>>>>>>>>>1

1x - 1y + 2z= 3>>>>>>>>>>>>>>>>>>>>2

=======================

2x // + 3z = 8

2x + 3z = 8 >>>>>>>>>>4

calculando >>>>>>>>>>>>>>>2 e >>>>>>3 (eliminando y )

1x -1y +2z=3>>>>>>>>>>>>>>>>>>>>2 ( - 1 )

3x-1y+5z =7>>>>>>>>>>>>>>>>>>>3

=================================

1x + 1y - 2z = -3 >>>>>>>>>>>>>2

3x - 1y + 5z = + 7 >>>>>>>>>>>>>>3

========================================

4x // + 3z = 4>>>>>>>>>>>>5

calculando>>>>>>>>>>4e >>>>>>>>>>>5

2x + 3z = 8 >>>>>>>>>>>4 ( - 1 )

4x + 3z = 4 >>>>>>>>>>>>>5

=====================================

- 2X - 3Z = - 8

4X +3Z = 4

=========================================

2X // = - 4

X = -4/2 = -2 >>>>>>>>>>RESPOSTA X

SUBSTITUI VALOR DE X POR -2 EM >>>>>>>4 OU >>>>>5

2X + 3Z = 8

2 ( - 2) + 3Z = 8

-4 + 3Z = 8

3Z = 8 + 4

3Z = 12

Z = 12/3 = 4 >>>>>>>RESPOSTA Z

SUSTITUINDO EM>>>>>>>>1 OS VALORES DE X POR -2 E VALOR DE Z POR 4

X - Y + 2Z = 3

-2 - Y + 2 ( 4 ) = 3

-2 - Y + 8 = 3

-Y + 6 = 3

- Y = 3 - 6

-Y = - 3 ( - 1)

Y = 3 >>>>>>RESPOSTA Y

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