Question

resolva o sistema linear
x+4y+3z=1
x-3y-2z=5
2x+5y+4z=4

Answer 1

Pelo Método de Gaus - Escalonamento

x + 4y + 3z = 1→ l1
x - 3y - 2z = 5 → l2
2x + 5y + 4z =4 →l3

x + 4y + 3z = 1→ l1
0 + 7y + 5z = -4 → l1 - l2 = l4
0 + 11y + 8z = -6 →l3 - 2*l2 = l5

x + 4y + 3z = 1→ l1
0 + 7y + 5z = -4 → l1 - l2 = l4
0 +  0 - z = -2 → -7/11*l5 + l4 = l6 

x + 4y + 3z = 1→ l1
0 + 7y + 5z = -4 → l1 - l2 = l4
0 +  0  + z = 2 → -7/11*l5 + l4 = (-1)* l6 = l7

7y + 5 z = - 4 ⇔ 7y + 5 (2) = - 4 ⇔ 7y = -14 ⇔ y = -14/7 ⇔ y = -2

x + 4(-2) + 3(2) = 1 ⇔ x - 8 + 6 = 1 ⇔ x - 2 = 1 ⇔ x = 3

S = {(3,-2,2)}

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30/03/2016
Sepauto - SSRC
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