Question

resolva o logaritmo
log (x − 1) + log (x + 2) = 1​

Answer 1

Resposta:

log (x − 1) + log (x + 2) = 1​

log (x-1)*(x+2) = 1

(x-1)*(x+2) = $10^{1}$

x² + 2x -1x -2 = 10

x² +x -2 -10 = 0

x² + x - 12 = 0

Soma = -1

Produto = -12

x = -4 ou x = 3