Question

resolva o limite
$\lim_{x \to \ 0} \frac{3x^{2} + x }{ x - 7x}$

Answer 1

Explicação passo-a-passo:

$lim_{x - > 0}( \frac{3x + x}{x - 7x} )$

$lim_{x - > 0}( \frac{x(3x + 1)}{x(1 - 7)} )$

$lim_{x - > 0}( \frac{3 x+ 1}{1 - 7} )$

$= \frac{3( 0) + 1}{ - 6}$

$= \frac{1}{ - 6}$

Answer 2

Resposta:

Lim (3x² + x)/( x - 7x)

x----0

Lim (3x² + x)/(-6x)

x----0

Lim x(3x + 1)/-6x    Simplifica x.

x----0

Lim (3x + 1)/-6

x----0

Lim -1/6 (3x + 1)

x----0

Lim -1/6(3.0 + 1)

x----0

Lim -1/6 ( 0 + 1)

x----0

Lim -1/6.1   = -1/6

x---0

Explicação passo-a-passo: