Question

Resolva o Cálculo:

Por favor me ajudem...essa questão vale prontos.....

Answer 1

Olá!
 
 
    $\left(1-\dfrac{1}{2}\right)^4+\left(1+\dfrac{1}{2}\right)^{-1}= \left(\dfrac{2-1}{2}\right)^4+\left(\dfrac{2+1}{2}\right)^{-1} = \\ \\ \\ = \left(\dfrac{1}{2}\right)^4 + \left(\dfrac{3}{2}\right)^{-1} = \dfrac{1^4}{2^4}+\dfrac{3^{-1}}{2^{-1}} = \dfrac{1}{16}+ \dfrac{\frac{1}{3}}{\frac{1}{2}} = \\ \\ \\ = \dfrac{1}{16} + \dfrac{1}{3}\cdot \dfrac{2}{1} = \dfrac{1}{16}+\dfrac{2}{3} = \dfrac{3+32}{48}=\dfrac{35}{48}.$



Bons estudos!