Question

Resolva, no intervalo 0 < x<2π, a equação: senx2
- 1 = 0

Answer 1

Olá!!

$\\ \sin^2 x - 1 = 0 \\\\ \sin^2 x = 1 \\\\ \sin x = \pm 1 \\\\ \boxed{x = \frac{\pi}{2}} \\\\ \boxed{x = \frac{3\pi}{2}}$