Question

Resolva

F) 9x²+12x-5=0
i) x²+20x+19=0
j) 25x²+100+64=0
k) 49x²-42x-95=0
h) n²+10n-9=0

Answer 1

f) 9x^2+12x-5=0
delta=b^2-4.a.c
delta=12^2-4.9.(-5)
delta=144+180
delta=324
x=-b-/+ raiz de delta/2a
x=-12-18/2.9
x=-30/18 :(6)
x= 5/3
x=-12+18/2.9
x=6/18 : (6)
x=1/3
i) x^2+20x+19=0
delta=b^2-4.a.c
delta=20^2-4.1.19
delta=400-76
delta=324
x=-b-/+ raiz de delta/2a
x=-20-18/2.1
x=-38/2
x=-19
x=-20+18/2.1
x=-2/2
x=-1