Question

Resolva essas equações

(X-6)(4x-8)=0

Answer 1

$4x^{2} -8x-24x+48 =0 \\ 4x^{2} -32x+48=0 \\ \\ b^{2} -4.(a).(c) \\ 1024-4(4)(48) \\ 1024-768 \\ = 256 \\ \\ \frac{ -b +- \sqrt{delta} }{2a} \\ 32+16 / 8 = x_{1} = 48/8 = 6 \\ 32-16/8 = x_{2} = 16/8 = 2$

Answer 2

4x^2-8x-24x+48=0
4x^2-32x+48=0
a=4 b=32 c=48
Δ=(b)^2-4(a)(c)
Δ=(32)^2-4(4)(48)
Δ=1024-768
Δ=256

X= -b±√Δ/2a
X= -(32)±√256/2•4
X=-32+16/8=6
E
X=-32-16/8=-6



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