Question

Resolva equação em formato de Bhaskara
2n^2+22n-1240=0
Me ajudem por favor

Answer 1

$2n^{2} + 22n - 1240 = 0 \\ a = 2; b = 22; c = -1240 \\ \\ \beta = b^{2} - 4ac \\ \beta = 22^{2} - 4(2)(-1240) \\ \beta = 484 + 9920 \\ \beta = 10.104 \\ \\ n = \frac{-b +- \sqrt{\beta}}{2a} \\ \\ n = \frac{-22 +- \sqrt{10.104} }{2\times2} \\ \\ n = \frac{-22 +- 102}{4} \\ \\ n' = \frac{-22 + 102}{4} = \frac{80}{4} = 20 \\ \\ n'' = \frac{-22 - 102}{4} = \frac{-124}{4} = -31 \\ \\ n' = 20 \\ n'' = -31$