resolva equação de 2 grau
x²+5X=0
x²-49=0
Soluções para a tarefa
x²+5x=0 Resposta: x²=-5
Explicação passo a passo:
1. Determine the quadratic equation’s coefficients a, b and c
Use the standard form,(ax²+bx+c=0) , to find the coefficients of our equation,
x²+5x+0=0:
a=1
b=5
c=0
2. Plug these coefficients into the quadratic formula
The quadratic formula gives us the roots for ax²+bx+c=0 , in which a, b and c are numbers (or coefficients), as follows:
x=(-b±sqrt(b^2-4ac))/(2a)
x=(-5±sqrt(25))/(2)
to get the result:
x=(-5±sqrt(25))/2
3. Simplify square root sqrt(25)
Simplify 25 by finding its prime factors:
The prime factorization of 25 is 5²
Write the prime factors:
sqrt(25)=sqrt(5*5)
Group the prime factors into pairs and rewrite them in exponent form:
sqrt(5*5)=sqrt(5^2)
Use the rule sqrt(x^2)=x to simplify further:
sqrt(5^2)=5
4. Solve the equation for x
x=(-5±5)/2
The ± means two answers are possible.
Separate the equations:
x_1=(-5+5)/2 and x_2=(-5-5)/2
x_1=(-5+5)/2
x_1=(-0)/2
x_1=-0
x_2=(-5-5)/2
x_2=(-10)/2
(Result final) x_2=-5
Desculpe não fazer a outra equação porque demora para calcular