Question

resolva em r as equações exponenciais 9/16^2x-1 = 4/3^-x+1

Answer 1

(9/16)^2x-1 = (4/3)^-x+1

[(3/4)²]^2x-1 = (4/3)^-x+1

(3/4)^4x-2 = (3/4)^x-1

4x-2 = x-1

4x-x = -1+2

3x = 1

x = 1/3

Answer 2

( 9/16)  = 3² / 4²  ou( 3/4)²
[( 3/4)²]²ˣ⁻¹ = ( 4/3)⁻¹⁺ˣ
( 3/4)⁴ˣ⁻² = ( 3/4 )¹⁻ˣ
4x - 2 = 1 - x
4x + x = 1 + 2
5x = 3
x = 3/5 ***