Question

Resolva em R as equações:

a)log3 (5x-6)=2
b)log7 (9x-1) = log7 (4-2x)

Answer 1

Aplicando a propriedade de log.

a)

$log_3\ (5x-6)=2\\\\ 3^2=5x-6\\\\ 9+6=5x\\\\ 5x=15\\\\ x=\frac{15}{5}\\\\ \boxed{x=3}$

b)

$log_7 (9x-1)=log_7\ (4-2x)\\\\ 9x-1=4-2x\\\\ 9x+2x=4+1\\\\ 11x=5\\\\ \boxed{x=\frac{5}{11}}$