Question

Resolva, em R, a equação abaixo

Answer 1

Resposta:

senx.cosx+1/2=1. (sen2x=senx.cosx)

senx.cosx+1/2=1. (sen2x=senx.cosx)sen2x=1/2

senx.cosx+1/2=1. (sen2x=senx.cosx)sen2x=1/22x=π/6+2kπ(1) ou 2x=5π/6 + 2kπ(2)

senx.cosx+1/2=1. (sen2x=senx.cosx)sen2x=1/22x=π/6+2kπ(1) ou 2x=5π/6 + 2kπ(2)(1)

senx.cosx+1/2=1. (sen2x=senx.cosx)sen2x=1/22x=π/6+2kπ(1) ou 2x=5π/6 + 2kπ(2)(1)x=π/12+kπ(k€R)

senx.cosx+1/2=1. (sen2x=senx.cosx)sen2x=1/22x=π/6+2kπ(1) ou 2x=5π/6 + 2kπ(2)(1)x=π/12+kπ(k€R)(2)

senx.cosx+1/2=1. (sen2x=senx.cosx)sen2x=1/22x=π/6+2kπ(1) ou 2x=5π/6 + 2kπ(2)(1)x=π/12+kπ(k€R)(2)x=5π/12+kπ(k€R)

senx.cosx+1/2=1. (sen2x=senx.cosx)sen2x=1/22x=π/6+2kπ(1) ou 2x=5π/6 + 2kπ(2)(1)x=π/12+kπ(k€R)(2)x=5π/12+kπ(k€R)(€ significa pertence