Question

RESOLVA EM IR AS EQUAÇÕES


a) -4 +2x = x + 12


b) $\frac{a}{3}$ + 3 = a + $\frac{1}{3}$

Answer 1

a) $-4+2x=x+12$

$2x-x=12+4$

$x=16$

b) $\frac{a}{3}+3=a+\frac{1}{3}$

$\frac{a}{3}-a=\frac{1}{3}-3$

$\frac{a}{3}-\frac{3a}{3}=\frac{1}{3}-\frac{9}{3}$

$-\frac{2a}{3}=-\frac{8}{3}$

$\frac{2a}{3}=\frac{8}{3}$

$2a=8$

$a=\frac{8}{2}$

$a=4$