Question

resolva em forma de bhaskara
5x2-20=0

Answer 1

$5x^2-20 = 0$

Báskara:
$\Delta= 0 - 4\times5\times(-20) = 400$


$x= \frac{-0\pm \sqrt{400} }{2\times5} = \frac{\pm20}{10} \\\\x'=-2\\\\x''=-2$