Question

Resolva e encontre as raízes das equações;
3x2 -6x = 0 e 8x2 - 28x = 0

Answer 1

Resposta:

A) $x=2,\:x=0$

B) $x=\frac{7}{2},\:x=0$

Explicação passo a passo:

A) $3x^2-6x=0$

$x_{1,\:2}=\frac{-\left(-6\right)\pm \sqrt{\left(-6\right)^2-4\cdot \:3\cdot \:0}}{2\cdot \:3}$

$x_{1,\:2}=\frac{-\left(-6\right)\pm \:6}{2\cdot \:3}$

$x_1=\frac{-\left(-6\right)+6}{2\cdot \:3},\:x_2=\frac{-\left(-6\right)-6}{2\cdot \:3}$

$x=2,\:x=0$

B) $8x^2-28x=0$

$x_{1,\:2}=\frac{-\left(-28\right)\pm \sqrt{\left(-28\right)^2-4\cdot \:8\cdot \:0}}{2\cdot \:8}$

$x_{1,\:2}=\frac{-\left(-28\right)\pm \:28}{2\cdot \:8}$

$x_1=\frac{-\left(-28\right)+28}{2\cdot \:8},\:x_2=\frac{-\left(-28\right)-28}{2\cdot \:8}$

$x=\frac{7}{2},\:x=0$