Matemática, perguntado por Erika1234567, 1 ano atrás

resolva com a formula de Bhaskara:
URGENTEEEEEEE
3x²+4x+1=0
x²-9x+20=0
-x²-4x+5=0
x²+3x-4=0
2x²-50=0
4x²+6x=0


Soluções para a tarefa

Respondido por melschaelder
1
3x²+4x+1=0

Δ=b²-4ac
a=3 b=4 c=1
Δ=4²-4.3.1
Δ=16-12
Δ=4

x=-b±√Δ
    _____
       2a

x= -4±√4
     ____
       2a

x= -4±2
     ____
       2.3
x1= -4+2
    ______
        6
 x1=  -2/6
x1= -3

x2= -4-2/6
x2=-6/6
x2= -1
 
S=(-3,-1)
_______________________________

x²-9x+20=0

a=1 b= -9 c= 20
Δ=b²-4ac
Δ= (-9)²-4.1.20
Δ= 81 - 80
Δ= 1

x=-b±√Δ
    _____
       2a
x= -(-9) ± √1 / 2.1
x= 9 ± 1/2
x1= 9+1/2
x1= 10/2
x1= 5
x2= 9-1/2
x2= 8/2
x2= 4 

S=(5,4)
__________________________________

-x²-4x+5=0

A= -1 B= -4 C=5
Δ=b²-4ac
Δ=(-4)²-4.(-1).5
Δ= 16+20
Δ= 36

x=-b±√Δ
    _____
       2a
x= -b±√Δ/2.a
x=-(-4)±√36/2.(-1)
x= 4±6/-2
x1= 4+6/-2
x1= 10/-2
x1= -5
x2= 4-6/-2
x2= -2/-2
x2= 1

S=(-5,1)
_______________________________

x²+3x-4=0

a=1 b=3 c= -4

Δ=b²-4ac
Δ=4²-4.1.(-4)
Δ=16-16
Δ=0

Obs: quando o delta for igual a zero, as raízes serão iguais.

x=-b±√Δ
    _____
       2a

x= -4±√Δ/2.a
x= -4±0/2.1
x1= -4+0/2
x1= -4/2
x1= -2

x2= -4-0/2
x2= -4/2
x2= -2

S=(-2,-2)
______________________________
 
2x²-50=0

2x² - 50 = 0
2x² = 50
x² = 50/2
x² = 25
x = √25
x = 5

_______________________________

4x²+6x=0
a=4 b=6 c=0

Δ=b²-4ac
Δ=6²-4.4.0
Δ=36-0
Δ=36

x=-b±√Δ
    _____
       2a
x=-6±√36/2.4
x=-6±6/8
x1= -6+6/8
x1=0/8 
x1= 0
x2= -6-6/8
x2= -12/8 simplifica por 2
x2= -6/4 simplifica por 2 dnv
x2= -3/2 (-1)
x2= 3/2


melschaelder: vou fazer as outras
melschaelder: x²-9x+20=0
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