resolva as seguintes proporçães
b)10=50
7 ×
c)1=×-6
7 49
d)5×+3=-21
10 30
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b) 10/7 = 50/x
10 • x = 7 • 50
10x = 350
x = 350/10
x = 35
c) 1/7 = x-6/49
7 • (x - 6) = 1 • 49
7x - 42 = 49
7x = 49 + 42
x = 49/42
x = 13
d) 5x+3/10 = -21/30
(5x + 3) • 30 = 10 • (-21)
150x + 90 = -210
150x = -210-90
150x = -300
x = -300/150
x = -2
espero ter ajudado :/
10 • x = 7 • 50
10x = 350
x = 350/10
x = 35
c) 1/7 = x-6/49
7 • (x - 6) = 1 • 49
7x - 42 = 49
7x = 49 + 42
x = 49/42
x = 13
d) 5x+3/10 = -21/30
(5x + 3) • 30 = 10 • (-21)
150x + 90 = -210
150x = -210-90
150x = -300
x = -300/150
x = -2
espero ter ajudado :/
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