RESOLVA AS SEGUINTES EXPRESSÕES NUMERICAS
2. { 23+4.{ 200 . 18 - 5 . ( 9 . 70 - 3 . 40 ) } } =
Soluções para a tarefa
Resposta: a=126(pode fazer direto)
b=-34(direto tbm)
c=0,81...x 24
19,44
d=25,5-6*-100
1659,5
e=1,9375-2,04
-0,1025
f=73*74
5402
g=25:5+8
5+8
13
h=(9+1)+10-10
10
i=9:3+3 x 4
2+12
14
j=70-[5 x 2+9]
70-19
61
k=11 x 9-8
11 x 1
11
l=25+8-2 x 12
31 x 12
372
m=36 ; 9+40-12
4+28
32
n=(49-1):5*5
48/25
1,92
o=16-10+(8-5)
16-10+3
6+3
9
p=30-(4+1)+8
30-5+8
25+8
32
q=30+[6^2/2+1]
30+[36/3]
30+12
42
r=20-[6-4*(10-9)+1]
20-[6-4*1+1]
20-[2*2]
20-4
16
s=50+[3^3/3+4*3]
50+[18/7*3]
50+[18/21]
50+0,8571...
50,8571
t=100-[5^2/5+12*1]
100-[25/17*1]
100-1,4705...
98,5295
u=[4^2+(125-12)]/(729-343)
[4^2+113]/386
[16+113]/386
129/386
0,3341
v=7^2+2*[(9+1)-4*1^3]
7^2+2*[10-4*1^3]
7^2+2*[6*1^3]
7^2+2*[6*1]
7^2+2*6
7^2+12
49+12
61
w=25+{3^3/9+[3^2*5-3*(8-5)]}
25+{3^3/9+[3^2*5-3*3]}
25+{3^3/9+[9*2*3]}
25+{3^3/9+54}
25+{12/9+54}
25+{1,333+54}
25+55,333
80,333
x=[(16+2*9)+(256/64)-35]^2+1^10-10^0
[162+4-35]^2+1^10-10^0
[26244+16-1225]
25035
y=4*4+{[9-8*12-5]*4}
4*4+{92*4}
4*4+368
16+368
384
z=25+{27/9+[9*5-3*(8-5)]}
25+{27/9+[9*5-3*3]}
25+{27/9+36}
25+39
64
Explicação passo-a-passo:esse * e vezes ok e / e dividir