Question

Resolva as seguintes equações de 2grau x2-3x+2=0

Answer 1

$\purple{\mathsf{Vamos~fazer!!!}}✍$

$\boxed{\begin{array}{lr}a = 1 \\ \\ b = - 3 \\ \\ c = 2\end{array}}$

Descobrindo faremos o delta.

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$\boxed{\begin{array}{lr} \green{ {x}^{2} - 3x + 2 = 0} \\ \\ Δ = {b}^{2} - 4ac \\ \\ Δ = 9 - 8\ \\ \\Δ = \red{1} \end{array}}$

Com base no delta agora vamos descobrir o valor de x.

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$\boxed{\begin{array}{lr} \green{x} = \frac{ - b ~±~\sqrt{Δ} }{2a} \\ \\ \\ \green{x} = \frac{3~±~1}{2} \end{array}}$

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$\mathtt{\blue{Resposta:}}$

• x = 1

ou

• x = 2

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$\boxed{\begin{array}{lr}\green{\infty}\mathbf{ \:By: ASWhiter}\end{array}}$

$\Huge{\mathbb{\blue{Espero~ter~ajudado!!!}}}$

Answer 2

Resposta:

Olá,

$\boxed{\begin{array}{lr} x^2 - 3x + 2 = 0\\a = 1\\b = -3\\c = 2\end{array}}$

$\boxed{\begin{array}{lr} \Delta = b^2 - 4ac\\\Delta = -3^2 - 4 \times 1 \times 2\\\Delta = 9 - 4 \times 1 \times 2\\\Delta = 9 - 4 \times 2\\\Delta = 9 - 8\\\Delta = 1 \end{array}}$

$\boxed{\begin{array}{lr} x = \dfrac{-b \pm \sqrt{\Delta}}{2a}\\\\x = \dfrac{-(-3) \pm \sqrt{1}}{2 \times 1}\\\\x = \dfrac{3 \pm 1}{2}\end{array}}$

$\boxed{\begin{array}{lr} x_1 = \dfrac{3 + 1}{2}\\\\x_1 = \dfrac{4}{2}\\\\x_1 = 2\end{array}}$

$\boxed{\begin{array}{lr} x_2 = \dfrac{3 - 1}{2}\\\\x_2 = \dfrac{2}{2}\\\\x_2 = 1\end{array}}$

Ω | Ass: Fallen Angel | Ω

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Espero ter ajudado!