Question

Resolva as seguintes equaçoes.

A) 2a+17 = 32


b) 3a dividido por 5 = 18

c) 21 = 43+2n dividido por 3 .

Answer 1

$a) \\ \\ 2a + 17 = 32 \\ \\ 2a = 32 - 17 \\ \\ 2a = 15 \\ \\ a= \dfrac{15}{2} \\ \\=\ \textgreater \ a = 7,5$

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$b) \\ \\ \dfrac{3a}{5} = 18 \\ \\ \\ 3a = 15 . 5 \\ \\ 3a = 90 \\ \\ \\ a = \dfrac{90}{3} \\ \\ \\ =\ \textgreater \ a =30$


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$c) \\ \\ 21 = \dfrac{43 + 2n}{3} \\ \\ 21 . 3 = 43 + 2n \\ \\ 63 = 43 + 2n \\ \\ 63 - 43 = 2n \\ \\ 20 = 2n \\ \\ 2n = 20 \\ \\ n = \dfrac{20}{2} \\ \\ =\ \textgreater \ n = 10$