Question

resolva as seguintes equaçoês:

a)12+16(8-2x)=2-8x

b)4x-8/6-16x+10/4=

Answer 1

$\boxed{\boxed{Ola\´\ Helida}}$

A)

$12+16(8-2x)=2-8x\\ \\ \\ 12+128-32x = 2-8x\\ \\ \\ 140-32x=2-8x\\ \\ \\ 140-2=-8x+32x\\ \\ \\ 138=24x\\ \\ \\ x=138\div24\\ \\ \\ x=\dfrac{138}{24} = \dfrac{23}{4}$

B)

$4x-\dfrac{8}{6} -16x+\dfrac{10}{4} =\\ \\ \\ 48x-16-192x+30=\\ \\ \\ -144x+14=\\ \\ \\ 14=144x\\ \\ \\ \dfrac{14}{144} = x$

Espero ter ajudado!

Answer 2

a)
$12 + 16(8 - 2x) = 2 - 8x \\ 12 + 128 - 32x = 2 - 8x \\ - 32x + 8x = 2 - 12 - 128 \\ - 24x = - 138 \\ x = \frac{138}{24} \\ x = \frac{23}{4}$