Question

RESOLVA AS SEGUINTES EQUAÇÃOS MODULARES

8+x=5

4x-5=13

x²-5=4

Answer 1

Resposta:

a) 8-5=x

3=x

b) 4x=13+5

4x= 18

x=18/4

x=4,5

c) x2=4+5

x2=9

x=3

Answer 2

[ x ] = x , se x > 0

[ x ] = - x , se x < 0

a)

| 8+x |=5

8 + x = 5

x = 5 - 8

x = - 3

e

- (8 + x ) = 5

- 8 - x = 5

- x = 5 + 8

- x = 13 .(-1)

x = - 13

{ x1 = - 3 e x2 = - 13 }

b)

[ 4x-5 ] =13

4x - 5 = 13

4x = 13 + 5

4x = 18

x = 18/4 ÷ (2)

x = 9/2

e

- ( 4x-5 )=13

- 4x + 5 = 13

- 4x = 13 - 5

- 4x = 8 .(-1)

4x = - 8

x = - 8/4

x = - 2

{ x1 = - 2 e x2 = 9/2 }

c)

[ x²-5 ]=4

x² - 5 = 4

x² = 4 + 5

x² = 9

x = \/9

x = + - 3

e

- [ x² - 5 ] = 4

- x² + 5 = 4

- x² = 4 - 5

- x² = - 1.(-1)

x² = 1

x= \/1

x =+ - 1

{ x1 = -1 , x2 = 1 , x3= 3 , x4 = - 3}