Question

Resolva as questões: 52x+20y=44. 10x-20y=80 me ajudemmm pfvr!​

Answer 1

$\large\boxed{\begin{array}{l}+\underline{\begin{cases}\sf 52x+\diagdown\!\!\!\!\!\!20y=44\\\sf 10x-\diagdown\!\!\!\!\!\!20y=80\end{cases}}\\\sf62x=124\\\sf x=\dfrac{124}{62}\\\\\sf x=2\\\sf 10x-20y=80\\\sf 10\cdot2-20y=80\\\sf 20y=20-80\\\sf 20y=-60\\\sf y=-\dfrac{6\backslash\!\!\!0}{2\backslash\!\!\!0}\\\sf y=-3\\\sf s=\{2,-3\}\end{array}}$