Question

Resolva as operações de segundo grau
a) x^2+5t+6=0
b)x^2-10x+21=0

Answer 1

$a) \: \: {x}^{2} + 5x + 6 = 0$
∆=b²-4ac
∆=5²-4×1×6
∆=25-24
∆=1

x= - b ±√∆ /2a

x= -5 ±1 /2
x¹=-2
x²=-3

S{-2, -3}


$b) {x}^{2} - 10x + 21$
∆= -10² -4×1×21
∆=100-96
∆=4

x= 10±2 /2
x¹=6
x²=4

S{6, 4}