Question

resolva as operações com frações a seguir:
2/5 + 1/5 =

3/8 - 1/8 =

1/10 + 8/10 =

1/2 + 1/5 =

3/4 - 1/6 =

4/8 + 1/10

Answer 1

Resposta:

$\frac{2}{5} + \frac{1}{5} = \frac{2 + 1}{5} = \frac{3}{5}$

$\frac{3}{8} - \frac{1}{8} = \frac{3 - 1}{8} = \frac{2}{8}$

$\frac{1}{10} + \frac{8}{10} = \frac{1 + 8}{10} = \frac{9}{10}$

$\frac{1}{2} + \frac{1}{5} = \frac{5 + 2}{10} = \frac{7}{10}$

$\frac{3}{4} - \frac{1}{6} = \frac{18 - 4}{24} = \frac{14}{24}$

$\frac{4}{8} + \frac{1}{10} = \frac{40 + 8}{80} = \frac{48}{80}$

Explicação passo-a-passo:

espero ter ayudado ✌

Answer 2

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$\sf\dfrac{2}{5}+\dfrac{1}{5}=\dfrac{3}{5}\blue{\checkmark}\\\sf\dfrac{3}{8}-\dfrac{1}{8}=\dfrac{2\div2}{8\div2}=\dfrac{1}{4}\blue{\checkmark}\\\sf\dfrac{1}{10}+\dfrac{8}{10}=\dfrac{9}{10}\blue{\checkmark}\\\sf\dfrac{1}{2}+\dfrac{1}{5}=\dfrac{5+2}{10}=\dfrac{7}{10}\\\sf\dfrac{3}{4}-\dfrac{1}{6}=\dfrac{9-2}{12}=\dfrac{7}{12}\blue{\checkmark}\\\sf\dfrac{4\div4}{8\div4}+\dfrac{1}{10}=\dfrac{1}{2}+\dfrac{1}{10}=\dfrac{5+1}{10}=\dfrac{6\div2}{10\div2}=\dfrac{3}{5}\blue{\checkmark}$