Question

resolva as opções com radicais :
$4 \sqrt{18} + 3 \sqrt{8} - 5 \sqrt{12} + 4 \sqrt{27}$
Me ajudem​

Answer 1

Oie, Td Bom?!

$= 4 \sqrt{8} + 3 \sqrt{8} - 5 \sqrt{12} + 4 \sqrt{27}$

$= 4 \sqrt{3 {}^{2} \: . \: 2} + 3 \sqrt{2 {}^{2} \: . \: 2} - 5 \sqrt{2 {}^{2} \: . \: 3 } + 4 \sqrt{3 {}^{2} \: . \: 3}$

$= 4 \sqrt{3 {}^{2} } \sqrt{2} + 3 \sqrt{2 {}^{2} } \sqrt{2} - 5 \sqrt{2 {}^{2} } \sqrt{3} + 4 \sqrt{3 {}^{2} } \sqrt{3}$

$= 4 \: . \: 3 \sqrt{2} + 3 \: . \: 2 \sqrt{2} - 5 \: . \: 2 \sqrt{3} + 4 \: . \: 3 \sqrt{3}$

$= 12 \sqrt{2} + 6 \sqrt{2} - 10 \sqrt{3} - 12 \sqrt{3}$

$= (12 + 6) \sqrt{2} +( - 10 + 12) \sqrt{3}$

$= 18 \sqrt{2} + 2 \sqrt{3}$

Att. Makaveli1996