Question

resolva as expressões numéricas
$a - \sqrt{36} + \sqrt{49}$
$b - ( - 2) {}^{2} - \sqrt{9}$
$c \: \: 9 {}^{0} - \sqrt{1}$
$d \: \: \sqrt{16 } - \sqrt{25}$
$e \: \: ( { - 2}^{3} ) - \sqrt{( - 3) {}^{4} }$

Answer 1

$a) \ \sqrt{36}+  \sqrt{49}=6+7=13\\ \\ b) \ (-2)^2-\sqrt9=(-2).(-2)-3=4-3=1\\ \\ c) \ 9^o-\sqrt1=1-1=0\\ \\ d) \ \sqrt{16} - \sqrt{25}=4-5=-1\\ \\ e) \ (-2^3)- \sqrt{(-3)^4}=-8-\sqrt{81}=-8-9=-17$