Question

resolva as equações.
x²-10x+25=0

Answer 1

Utiliza Baskara 
onde que a = 1 b=-10 c =25

Formula = -b+ou- (b^2-4.a.c)^1/2 /2.a
 Substituindo Terá : 

10+ou- (100 -4 ,1 .25)^1/2 /2

10+ou- 0/2

X1= 10+0 /2  = 5

X2 = 10-0 /2 = 5

Answer 2

Resposta:

$S=\{5\}$

Explicação passo-a-passo:

$x^{2} -10x+25=0\\\\a=1\\b=(-10)\\c=25$

$\Delta=b^{2} -4ac\\\Delta=(-10)^{2}-4\times1\times25\\\Delta=100-100\\\Delta=0$

$x=\frac{-b\pm\sqrt{\Delta} }{2a} \\\\x=\frac{-(-10)\pm\sqrt{0} }{2\times1} \\\\x=\frac{10\pm0}{2}$

$x_{1} =\frac{10+0}{2} =\frac{10}{2} =5\\\\x_{2}=\frac{10-0}{2}=\frac{10}{2} =5$